Nearest Ancestor Node In Jquery
Solution 1:
Edit: Since jQuery 1.3, this has been built in as the closest()
function. eg: $('#foo').closest('.bar');
yep - parents() traverses up the tree.
<div id="a">
<div id="b">
<p id="c">
<a id="d"></a>
</p>
</div>
</div>
$('#d').parents("div:first");
will select div b.
Solution 2:
Adding to @nickf's answer:
jQuery 1.3 simplifyed this task with closest
.
Given a DOM:
<div id="a">
<div id="b">
<p id="c">
<a id="d"></a>
</p>
</div>
</div>
You can do:
$('#d').closest("div"); // returns [ div#b ]
[Closest returns a] set of elements containing the closest parent element that matches the specified selector, the starting element included.
Solution 3:
You should use closest
, because parents
won't give you the result you expect if you're working with multiple elements. For instance, let's say you have this:
<divid="0"><divid="1">test with <b>nested</b> divs.</div><divid="2">another div.</div><divid="3">yet <b>another</b> div.</div></div>
and you want to add a class to the divs that have a <b>
element as their immediate child (ie, 1 and 3). If you use $('b').parents('div')
, you get divs 0, 1 and 3. If you use $('b').parents('div:first')
, you only get div 1. To get 1 and 3, but not 0, you have to use $('b').closest(elem)
.
Solution 4:
closest() starts at current element, if the parent you are looking for has the same tag as current (eg. both are divs), use parent().closest()
Post a Comment for "Nearest Ancestor Node In Jquery"